Calculating Critical Velocity

If you wanted to find the critical velocity for water moving through a section of pipe, we'll start out by using the basic formula for calculating critical velocity: Vcrit = (Nr_µ) / (D_ρ). In this equation, Vcrit represents critical velocity, Nr represents the Reynolds number, µ (mu) represents the coefficient of viscosity (i.e., the resistance to flow) for a given liquid, D represents the inner diameter of the pipe, and ρ (rho) represents the density of the given liquid. The µ (mu) variable is measured in meters-squared per second and the density of the given liquid is measured in kilograms per meter-squared.

Say you have a two meter-long section of pipe with an inner diameter of 0.03 meters, and you want to know the critical velocity of water passing through that section of pipe at a velocity of 0.25 meters per second, represented by V. Although µ varies with temperature, its typical value is 0.00000114 meters-square per second, so we will use this value in this example. The density, or ρ, of water is one kilogram per cubic meter.

If the Reynold's number is not given, you can calculate it using the formula: Nr = ρ_V_D/µ. Laminar flow is represented by a Reynold's number of less than 2,320, and turbulent flow is represented by a Reynold's number of greater than 4,000.

Plug in the values for each of the variables of the Reynold's number equation. After plugging in the values, the Reynold's number is 6,579. Because it is greater than 4,000, the flow is considered turbulent.

Now plug in the values to the critical velocity equation, and you should get: Vcrit = (6,579_0.000000114 meters/second-squared) / (0.03 meters_1 kilogram/cubic meter) = 0.025 meters/second.