How to Calculate the Distance/Speed of a Falling Object

By Jack Brubaker

Galileo first posited that objects fall toward earth at a rate independent of their mass. That is, all objects accelerate at the same rate during free-fall. Physicists later established that the objects accelerate at 9.81 meters per square second, m/s^2, or 32 feet per square second, ft/s^2; physicists now refer to these constants as the acceleration due to gravity, g. Physicists also established equations for describing the relationship between the velocity or speed of an object, v, the distance it travels, d, and time, t, it spends in free-fall. Specifically, v = g * t, and d = 0.5 * g * t^2.

Step 1

Measure or otherwise determine the time, t, the object spends in free-fall. If you are working a problem from a book, this information should be specifically stated. Otherwise, measure the time required for an object to fall to the ground using a stopwatch. For purposes of demonstration, consider a rock dropped from a bridge that strikes the ground 2.35 seconds after it is released.

Step 2

Calculate the velocity of the object at the moment of impact according to v = g * t. For the example given in Step 1, v = 9.81 m/s^2 * 2.35 s = 23.1 meters per second, m/s, after rounding. Or, in English units, v = 32 ft/s^2 * 2.35 s = 75.2 feet per second, ft/s.

Step 3

Calculate the distance the object fell according to d = 0.5 * g * t^2. In keeping with the scientific order of operations, you must calculate the exponent, or t^2 term, first. For the example from Step 1, t^2 = 2.35^2 = 5.52 s^2. Therefore, d = 0.5 * 9.81 m/s^2 * 5.52 s^2 = 27.1 meters, or 88.3 feet.