How Do I Calculate Capacity?

The capacity of a container is another word for the volume of material it will hold. It's usually measured in liters or gallons. It isn't the same as the volume the container would displace it you immersed it in water. The difference between these two quantities is the thickness of the container walls. This difference is negligible if the container is made from a thin material, but for wooden or concrete containers with walls that can be several inches thick, it isn't. When measuring capacity, it's always best to measure the inside dimensions. If you don't have access to the inside, you need to know the thickness of the container walls to get an accurate result.

You find the volume V of a rectangular container by measuring its length (l), width (w) and height (h) and multiplying these quantities.

\(V=l\times w\times h\)

You express the result in cubic units. For example, if you measure in feet, the result is in cubic feet, and if you measure in centimeters, the result is in cubic centimeters (or milliliters). Because capacity is usually expressed in liters or gallons, you'll probably have to convert your result using an appropriate conversion factor.

If you have access to the inside of the container, you can measure the inside dimensions and calculate capacity directly, using the formula for volume. If you can only measure the outside dimensions, but you know that the walls, base and top are of uniform thicknesses, you must subtract twice the wall thickness and twice the base thickness from each of these measurements first. If the wall and base thickness is t, the capacity is given by:

\(\text{capacity} = (l-2t)(w-2t)(h-2t)\)

If you know that the container's walls, base and top have different thicknesses, use those instead of 2t. For example, if you know that a container has a base that's 1 inch thick and a lid that's 2 inches thick, the height would be h – 3.

​Cubic Container:​ A cube is a special type of rectangular container that has three sides of equal length l. ​**The volume of a cube is thus l³**​. If you measure from the outside, and the thickness of the walls is t, the capacity is given by:

\(\text{capacity} = (l-2t)^3\)

To calculate the volume of a cylinder of length or height h and circular cross-section of radius r, use this formula:

\(V=\pi \times r^2 \times h\)

When measuring a closed container from the outside, you need to subtract the wall thickness (t) from the radius and the lid/base thickness from the height. The capacity formula then becomes (using a uniform thickness for the base and lid):

\(\text{capacity} = \pi\times(r-t)^2\times (h-2t)\)

Note that you don't double the wall thickness before subtracting it from the radius because the radius is a single line from the center to the outside of the circular cross-section.

In practice, it can be easier to measure diameter (d) than radius, since diameter is just the farthest distance between the edges of the cylinder. Diameter is equal to twice the radius (d = 2r, so r = [1/2]d), and the volume formula becomes:

\(V=\frac{\pi \times d^2\times h}{4}\)

The capacity is then (again using a uniform thickness):

\(\text{capacity} = \frac{\pi\times(d-2t)^2\times (h-2t)}{4}\)

You double the wall thickness because the diameter line crosses over the walls twice.

​The volume of a sphere of radius r is:​

\(V=\frac{4}{3} \pi r^3\)

If you manage to measure the radius from the outside (this might be difficult), and the sphere has walls of thickness t, its capacity is:

\(\text{capacity} = \frac{4}{3} \pi (r-t)^3\)

The volume of a pyramid with base dimensions l and w and height h is:

\(V=\frac{Ah}{3}=\frac{lwh}{3}\)

If the pyramid has walls of thickness t, and you measure from the outside, its capacity is approximately given by:

\(\text{capacity}=\frac{(l-2t)(w-2t)(h-2t)}{3}\)

This is approximate because the walls are angled, and you must consider the angle when calculating t. In most cases, the difference is small enough to ignore.

The volume of a cone of base radius r and height h is:

\(V=\frac{\pi r^2 h}{3}\)

If you measure from the outside, and its walls have a thickness t, the capacity is:

\(\text{capacity}=\frac{\pi (r-t)^2 (h-t)}{3}\)