Urea, chemical formula H2N-CO-NH2, is a metabolite or waste product eliminated by the kidneys. It is a colorless solid and an important source of nitrogen in fertilizers. Although it may be applied to the ground as a solid, it is often applied as a water-based solution of specific concentration. Making such a solution is not difficult to accomplish if one has the minimal equipment needed and is familiar with the concept of molecular weight. There are two methods of identifying urea concentration in solution: percentage by weight—whether of urea or “as nitrogen”—and molarity.
Research and Calculate Needed Information and Choose Solution Type Desired
Percent-by-weight: if, for example, a 4 percent solution is desired, place the beaker on the scale and using the scoop, weigh 40 g of urea and 960 g of water. Stir them together until thoroughly dissolved and uniform, and the job is complete.
By molarity: if a one-quarter molar solution is desired (0.250 molar), weigh into the beaker 15 grams urea (one-fourth of one molecular weight of urea) and, while stirring, add water until reaching the 1-liter mark of the beaker.
Percent-by-weight nitrogen: if a 3 percent-by-weight solution, by weight as nitrogen is desired, first calculate what the percentage would be as percent urea: 3 weight percent nitrogen x (60 / 28) = 6.5 weight percent urea.
Look up the atomic weights of the elements in urea and calculate its molecular weight. Doing so gives hydrogen, 1; nitrogen, 14; carbon, 12; and oxygen, 16. Since there are four hydrogen atoms, two nitrogen atoms, one carbon atom and one oxygen atom, the molecular weight of urea calculates as: (4 x 1) + (2 x 14) + 12 + 16 = 60.
Calculate the percentage of nitrogen in urea and look up the definition of molarity. Of urea’s 60 molecular weight, 28 is nitrogen, and the percentage of nitrogen in urea is calculated as: (28 / 60) x 100 percent = 47 percent.
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The definition of molarity is, according to Princeton’s Wordnet Search: “concentration measured by the number of moles of solute per liter of solution.”
The word “mole” is short for a molecular weight in grams of a substance. For urea, this is 60 g per liter of solution.
Make the solution in one of three ways (examples provided below):
Thus add 65 g urea to 935 g of water, using the methodology in item 1.