When you conduct a survey, you want to make sure that you have enough people involved so that the results will be statistically significant. However, the larger your survey, the more time and money you will have to spend to complete it. To maximize your results and minimize your cost, you need to plan ahead to determine the sample size of the survey before you begin.
- Z-Score chart (see resources)
- Calculator
Select your confidence interval and call this "C." The confidence interval is the range within which the true proportion is expected to fall. For example, if you wanted the range to be within 3 percent above or below the percentage from your survey, you would use 0.03 for C.
Select your confidence level. This is the percentage of the time that the true proportion will lie within your confidence interval. The more important the study, the higher the confidence level. For example, a medical study may require a 99 percent confidence level, while a poll for a local election may only desire a 90 percent confidence level.
Convert your confidence level into a z-score, using the z-score chart, and call it "Z." For example, a 99 percent confidence interval would result in a z-score of 2.58.
Estimate the percentage of people who will select the majority option and call this "P." For example, if you expect 58 percent of the people to vote for the Democratic candidate, you would use 0.58 for P.
Plug your values for C, Z and P into the following equation to determine how large you need your sample size to be: (Z^2 * P * (1 - P))/C^2. For example, if you had a z-score of 2.58, a percentage of 0.58 and a confidence interval of 0.03, you would plug those numbers in to make your expression (2.58^2_0.58_(1-0.58))/0.03^2, which comes out to be 1801.67, meaning your sample size would need to be 1,802 people.
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About the Author
Mark Kennan is a writer based in the Kansas City area, specializing in personal finance and business topics. He has been writing since 2009 and has been published by "Quicken," "TurboTax," and "The Motley Fool."
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