WEBVTT
1
00:00:00.840 --> 00:00:03.189 A:middle L:90%
okay, we know if Alexis X to the fourth
2
00:00:03.200 --> 00:00:04.839 A:middle L:90%
. Therefore, the change in X, or Delta
3
00:00:04.849 --> 00:00:09.320 A:middle L:90%
X is negative 0.1 Access to their fur off of
4
00:00:09.320 --> 00:00:14.619 A:middle L:90%
two minus 0.1 to the fourth. Power is to
5
00:00:14.619 --> 00:00:20.449 A:middle L:90%
to the fourth time's one minus four come 0.1 over
6
00:00:21.679 --> 00:00:27.149 A:middle L:90%
two, which is equivalent to 15.968