How To Find The Vertex Of A Parabola Equation

In the real world, parabolas describe the path of any thrown, kicked or fired object. They're also the shape used for satellite dishes, reflectors and the like, because they concentrate all rays that enter them into a single point inside the bell of the parabola, called the focus. In mathematical terms, a parabola is expressed by the equation f(x) = ax^2 + bx + c. Finding the midpoint between the parabola's two x-intercepts gives you the x-coordinate of the vertex, which you can then substitute into the equation to find the y-coordinate as well.

Step 1

Use basic algebra to write the parabola's equation in the form f(x) = ax^2 + bx + c, if it is not in that form already.

Step 2

Identify which numbers are represented by a, b and c in the parabola's equation. If b and c aren't present in the equation, it means they are equal to zero. The number represented by a, however, will never be equal to zero. For example, if your parabola's equation is f(x) = 2x^2 + 8x, then a = 2, b = 8 and c = 0.

Step 3

To find the midpoint between the parabola's two x-intercepts, calculate -b/2a, or negative b divided by twice the value of a. This gives you the x-coordinate of the vertex. To continue the example above, the x-coordinate of the vertex would be -8/4, or -2.

Step 4

Find the y-coordinate of the vertex by substituting the x-coordinate back into the original equation, then solving for f(x). Substituting x = -2 into the example equation would look like this: f(x) = 2(-2)^2 + 8(-2) = 2(-4) – 16 = 8 – 16 = -8. The solution, -8, is the y-coordinate. So the coordinates of the vertex for the example parabola are (-2, -8).